Math Problem Statement

Solve the following equations using the LCD. NOTE: You must check all answers

Solve the following equations using the LCD. NOTE: You must check all answers

Solution

I have displayed the image you uploaded. Let's solve the given rational equations using the least common denominator (LCD) method. I'll begin by extracting each equation and solving them step by step. Here are the equations:

  1. 5x+45x=3x\frac{5}{x} + \frac{4}{5x} = \frac{3}{x}
  2. 32y=5y2\frac{3}{2y} = \frac{5}{y^2}
  3. xy2=2y+3\frac{x}{y-2} = \frac{2}{y+3}

Let's start by solving the first equation:

1. 5x+45x=3x\frac{5}{x} + \frac{4}{5x} = \frac{3}{x}

  • The least common denominator (LCD) is 5x5x.
  • Multiply both sides by the LCD to eliminate the denominators.

I'll perform the calculations and provide the solution next.It seems there are no real solutions for the first equation 5x+45x=3x\frac{5}{x} + \frac{4}{5x} = \frac{3}{x}. This likely means that no value of xx satisfies the equation without introducing contradictions, such as division by zero.

Now, let's proceed to solve the second equation:

2. 32y=5y2\frac{3}{2y} = \frac{5}{y^2}

  • The least common denominator (LCD) is 2y22y^2.
  • I'll multiply both sides by the LCD and solve the equation.The solution to the second equation 32y=5y2\frac{3}{2y} = \frac{5}{y^2} is:

y=103y = \frac{10}{3}

Let's now move on to the third equation:

3. xy2=2y+3\frac{x}{y-2} = \frac{2}{y+3}

I'll solve this equation by cross-multiplying both sides.It seems like I can’t do more advanced data analysis right now. Please try again later. However, I can still assist with explanations or walk you through how to solve the equations manually if you'd like. Let me know how you'd like to proceed!

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Math Problem Analysis

Mathematical Concepts

Rational Equations
Least Common Denominator (LCD)
Cross-Multiplication

Formulas

LCD method: Multiply all terms by the least common denominator to eliminate fractions
Cross-multiplication: a/b = c/d becomes ad = bc

Theorems

Fundamental Theorem of Algebra

Suitable Grade Level

Grades 9-12