Math Problem Statement
Solution
The image shows the inequality:
To solve this inequality, let's break it down into steps:
Step 1: Factorize the expressions
Both and are difference of squares, so we can factor them:
So the inequality becomes:
Step 2: Determine the critical points
The critical points, where the expression equals zero, occur at:
Step 3: Analyze the intervals
The critical points divide the number line into five intervals:
We need to check the sign of the product within each interval.
Step 4: Check the sign in each interval
- Interval : All four factors are negative, so the product is positive.
- Interval : is positive, and the others are negative, so the product is negative.
- Interval : and are positive, and are negative, so the product is positive.
- Interval : is negative, and the others are positive, so the product is negative.
- Interval : All four factors are positive, so the product is positive.
Step 5: Identify where the product is less than or equal to zero
The product is negative or zero in the intervals and , including the critical points where the product equals zero.
Final Answer:
The solution to the inequality is:
[ [-2, -1] \cup [1, 2] ]
Would you like any further details or have any questions?
Here are 5 questions that relate to this problem:
- How can inequalities with higher-degree polynomials be solved?
- What is the significance of the difference of squares in factorization?
- How do you determine the sign of a polynomial over an interval?
- How would the solution change if the inequality were strict (i.e., instead of )?
- What are some common mistakes when solving polynomial inequalities?
Tip: When solving polynomial inequalities, always check the sign of the product within each interval created by the critical points.
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Math Problem Analysis
Mathematical Concepts
Inequalities
Polynomials
Factorization
Critical Points
Sign Analysis
Formulas
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Theorems
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Suitable Grade Level
Grades 10-12