We are given that:

1. The area of the land is 21 square feet.
2. The length of the land is 4 feet more than its width.

Let:

• $w$ represent the width of the land in feet.
• The length is then $w + 4$ feet (since it’s 4 feet more than the width).

Using the formula for the area of a rectangle: $\text{Area} = \text{Length} \times \text{Width}$

Substituting the values: $21 = (w + 4) \times w$

Thus, the length is represented as $w + 4$ feet.

Would you like me to proceed with solving for $w$ (the width), or provide more details?

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Here are 5 related questions for deeper understanding:

1. How do you solve quadratic equations formed in geometry problems like this?
2. What are other real-life applications of solving for area and perimeter in gardening?
3. Can the quadratic equation have more than one solution in such contexts?
4. How would the problem change if the land’s area were increased?
5. What are the different shapes of land area that could have been used?

Tip: Always label your variables clearly when working with word problems to keep track of what each one represents.