Math Problem Statement
A ball is thrown downward with a speed of 48ft/s from the top of a building that is 87 feet tall. After t seconds, its height above the ground in feet is given by s(t)=−16t^2−48t+87. When is the ball at a height of 59ft? Enter an exact answer.
Solution
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Math Problem Analysis
Mathematical Concepts
Quadratic Equations
Kinematics
Algebra
Formulas
Quadratic equation formula: ax^2 + bx + c = 0
Kinematic equation: s(t) = −16t^2−48t+87
Quadratic Formula: t = (-b ± √(b^2 - 4ac)) / 2a
Theorems
Quadratic Formula
Suitable Grade Level
Grades 9-10
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