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The image contains a set of problems involving percentages. Here’s a breakdown and solution for each of the calculations:

1. **48 is 40% of n**
   - The equation: \( 48 = 0.40 \times n \)
   - To solve for \( n \), divide both sides by 0.40:
     \[
     n = \frac{48}{0.40} = 120
     \]

2. **21 is n% of 84**
   - The equation: \( 21 = \frac{n}{100} \times 84 \)
   - To solve for \( n \), multiply both sides by 100 and divide by 84:
     \[
     n = \frac{21 \times 100}{84} = 25
     \]

3. **18% of 27 is n**
   - The equation: \( n = \frac{18}{100} \times 27 \)
   - To find \( n \), multiply 18% by 27:
     \[
     n = 0.18 \times 27 = 4.86
     \]

### Summary of Solutions:
1. \( n = 120 \)
2. \( n = 25 \)
3. \( n = 4.86 \)

Would you like more details or further assistance with these problems? Here are some related questions:

1. How would you solve a percentage problem when the percentage is greater than 100%?
2. What is the process to calculate percentages in real-world applications like discounts or taxes?
3. How do you convert a percentage to a decimal for calculation?
4. Can percentages be negative, and what does that mean in context?
5. How would you interpret a percentage that represents part of a whole, for example, "30% of a population"?

**Tip:** Always ensure that percentages are converted to decimals before performing multiplication or division.

48 is 40% of n, 21 is n% of 84, 18% of 27 is n

Learn how to solve percentage problems, including calculating the whole when given a part and percentage, finding the percentage, and determining the part. Examples include '48 is 40% of n,' '21 is n% of 84,' and '18% of 27 is n.' Suitable for Grades 5-7 students.

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