Math Problem Statement

  1. Pair of linear equation solution

Solution

I see you've uploaded three images. Let me first extract the relevant content from them and focus on the solution for the pair of linear equations mentioned in image 3.

Please give me a moment while I work on this.In the third image, you mentioned the topic of solving a "pair of linear equations." Let me extract and solve the relevant equations.

From image 3, the extracted problem regarding a pair of linear equations is:

Pair of linear equations:
3x + 4y = 1 
5x - 2y = 9 

To solve this system of equations:

We can solve this pair of linear equations using either the substitution method, elimination method, or matrix method. Let's proceed with the elimination method.

The equations are:

  1. 3x+4y=13x + 4y = 1 (Equation 1)
  2. 5x2y=95x - 2y = 9 (Equation 2)

Step 1: Make the coefficients of yy the same

Multiply Equation 1 by 2 and Equation 2 by 4 to align the coefficients of yy.

2(3x+4y)=2(1)becomes6x+8y=22(3x + 4y) = 2(1) \quad \text{becomes} \quad 6x + 8y = 2 4(5x2y)=4(9)becomes20x8y=364(5x - 2y) = 4(9) \quad \text{becomes} \quad 20x - 8y = 36

Step 2: Add the two equations

(6x+8y)+(20x8y)=2+36(6x + 8y) + (20x - 8y) = 2 + 36 26x=3826x = 38

Step 3: Solve for xx

x=3826=1913x = \frac{38}{26} = \frac{19}{13}

Step 4: Substitute x=1913x = \frac{19}{13} into one of the original equations

Substituting into Equation 1: 3(1913)+4y=13\left(\frac{19}{13}\right) + 4y = 1 5713+4y=1\frac{57}{13} + 4y = 1 4y=157134y = 1 - \frac{57}{13} 4y=13135713=44134y = \frac{13}{13} - \frac{57}{13} = \frac{-44}{13} y=4413×4=4452=1113y = \frac{-44}{13 \times 4} = \frac{-44}{52} = \frac{-11}{13}

Solution:

The solution to the pair of linear equations is: x=1913,y=1113x = \frac{19}{13}, \quad y = \frac{-11}{13}

Would you like further clarification on any of these steps?

Here are 5 related questions for practice:

  1. Solve the system: 2x3y=52x - 3y = 5 and 4x+y=74x + y = 7.
  2. How do you graphically represent the solution of two linear equations?
  3. What are the conditions for a system of equations to have no solution?
  4. Solve using the substitution method: x+2y=7x + 2y = 7 and 3xy=53x - y = 5.
  5. Can two linear equations be solved if their lines are parallel?

Tip: When using the elimination method, ensure you align one variable's coefficients to simplify the system easily.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Systems of Equations
Elimination Method

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12