Math Problem Statement
My favourite paint comes in 1L,2L,3L and 5L tins. I bought 13 tins and a total of 29L of paint. When I got home, I noticed that I had bought a different number of tins of each size but at least one of each. How many 3L tins did I buy?
Solution
Let's break down the problem step by step.
You have:
- 1L tins:
- 2L tins:
- 3L tins:
- 5L tins:
Given:
- The total number of tins is .
- The total volume of paint is liters.
- You bought at least one tin of each size, so , , , and .
We need to determine the value of (the number of 3L tins).
Step 1: Adjust for the minimum number of tins
Since each , subtract 1 from each variable to simplify:
Now, we rewrite the equations:
Simplify the second equation:
So,
Step 2: Trial and Error to Find a Solution
Now, we try different combinations to satisfy these conditions:
-
Let , , , :
- Total number of tins:
- Total liters of paint: (Too high)
-
Let , , , :
- Total number of tins:
- Total liters of paint: (Still too high)
-
Let , , , :
- Total number of tins:
- Total liters of paint:
This satisfies the condition, so the original number of 3L tins is:
Conclusion:
You bought 3 tins of 3L paint.
Would you like to go through more details, or do you have any questions?
Here are some related questions:
- What is the minimum number of tins needed to achieve a total of 29L?
- How would the solution change if you had bought 30L of paint?
- What if you had bought 14 tins instead of 13?
- Can this problem be solved using a different method like matrix algebra?
- How does changing the size of one tin type affect the total?
Tip: When solving combinatorial problems like this, breaking it down into smaller parts often makes it easier to find the correct answer.
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Math Problem Analysis
Mathematical Concepts
Linear equations
Combinatorial mathematics
Formulas
Equation solving
Trial and error approach
Theorems
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Suitable Grade Level
Grades 7-9
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