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The worksheet appears to be focused on solving one- and two-step equations, with examples provided for each problem. Let's go through the steps to solve these equations:

### 1. \( x + 12 = 20 \)
- **Step 1:** Subtract 12 from both sides:
  \[
  x = 20 - 12 = 8
  \]
  The solution is \( x = 8 \).

### 2. \( 2f = 14 \)
- **Step 1:** Divide both sides by 2:
  \[
  f = \frac{14}{2} = 7
  \]
  The solution is \( f = 7 \).

### 3. \( p - 13 = 12 \)
- **Step 1:** Add 13 to both sides:
  \[
  p = 12 + 13 = 25
  \]
  The solution is \( p = 25 \).

### 4. \( -4x = 24 \)
- **Step 1:** Divide both sides by -4:
  \[
  x = \frac{24}{-4} = -6
  \]
  The solution is \( x = -6 \).

### 5. \( 2x - 8 = 6 \)
- **Step 1:** Add 8 to both sides:
  \[
  2x = 6 + 8 = 14
  \]
- **Step 2:** Divide both sides by 2:
  \[
  x = \frac{14}{2} = 7
  \]
  The solution is \( x = 7 \).

### 6. \( \frac{y}{5} + 7 = 9 \)
- **Step 1:** Subtract 7 from both sides:
  \[
  \frac{y}{5} = 9 - 7 = 2
  \]
- **Step 2:** Multiply both sides by 5:
  \[
  y = 2 \times 5 = 10
  \]
  The solution is \( y = 10 \).

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Would you like further details on any of the steps or additional explanations?

Here are 5 relative questions to deepen your understanding:
1. How do you solve equations involving negative coefficients?
2. What are one-step and two-step equations, and how do they differ?
3. How would you check if your solution is correct for each problem?
4. How can equations involving fractions be simplified before solving?
5. What strategy would you use if there are variables on both sides of the equation?

**Tip:** Always isolate the variable by performing the opposite operation, such as subtracting when there is addition or dividing when there is multiplication.

Solve each one- and two-step equation and check your solution.

Learn how to solve one- and two-step linear equations such as x + 12 = 20 and 2f = 14 with step-by-step explanations. This worksheet covers fundamental algebraic techniques suitable for Grades 7-9.

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