The problem presented is:

$\log_2(x - 12) = 4$

To solve for $x$, follow these steps:

Step 1: Rewrite the logarithmic equation in exponential form

Since $\log_2(x - 12) = 4$, we can rewrite it as: $x - 12 = 2^4$

Step 2: Calculate $2^4$

$2^4 = 16$ So, $x - 12 = 16$

Step 3: Solve for $x$

Add 12 to both sides: $x = 16 + 12$ $x = 28$

Answer:

$x = 28$

Would you like further details, or do you have any questions about this process?

Related Questions

1. How would you solve $\log_3(x - 5) = 2$?
2. What if the equation was $\log_5(2x + 1) = 3$?
3. How do you convert a logarithmic equation into an exponential equation?
4. What is the value of $x$ in $\log_4(x + 3) = 5$?
5. How can you solve equations involving natural logarithms, like $\ln(x - 2) = 3$?

Tip

When solving logarithmic equations, remember that $\log_b(a) = c$ translates to $a = b^c$. This is often the key step in finding solutions.