The expression you provided is:

\[
\frac{\ln(100)}{100^2}
\]

Let's break it down and solve it step by step:

1. First, calculate \( \ln(100) \). Using a calculator or known values, we find:
   \[
   \ln(100) \approx 4.6052
   \]

2. Next, calculate \( 100^2 \):
   \[
   100^2 = 10000
   \]

3. Now, divide \( \ln(100) \) by \( 100^2 \):
   \[
   \frac{4.6052}{10000} = 0.00046052
   \]

Thus, the result of the expression is approximately:

\[
0.00046052
\]

Would you like a more detailed explanation or have any questions?

Here are 5 related questions to expand on this:

1. What is the derivative of \( \ln(x) \)?
2. How does the logarithmic function behave for values of \( x \) greater than 1?
3. What is the difference between \( \ln(x) \) and \( \log(x) \)?
4. How can you use natural logarithms to solve exponential equations?
5. How would the result change if the base of the logarithm was different (e.g., \( \log_{10}(x) \))?

**Tip:** When dealing with logarithms, remember that \( \ln(x) \) refers to the natural logarithm, which has a base \( e \approx 2.718 \).

Discover how to calculate ln(100)/100^2 step by step, using natural logarithms and exponentiation. This solution explores key concepts such as logarithmic properties and exponent laws, ideal for students in Grades 10-12.

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