To solve the inequality \( 7 - 3s \geq 1 \):

### Step 1: Isolate the variable term.
Subtract 7 from both sides:
\[
7 - 3s - 7 \geq 1 - 7
\]
\[
-3s \geq -6
\]

### Step 2: Solve for \( s \).
Divide both sides by -3. Remember that when dividing or multiplying both sides of an inequality by a negative number, the inequality sign flips.
\[
s \leq \frac{-6}{-3}
\]
\[
s \leq 2
\]

### Final Answer:
\[
s \leq 2
\]

Would you like further clarification on any step?

### Related Questions:
1. What is the difference between solving an equation and an inequality?
2. How do we handle inequalities when multiplying or dividing by negative numbers?
3. Can you provide an example where you multiply both sides of an inequality by a negative number?
4. How would the solution change if the inequality were \( 7 - 3s > 1 \)?
5. What would the solution be for \( 7 - 3s \geq 0 \)?

### Tip:
Always remember to reverse the inequality when dividing or multiplying by a negative number!

Discover how to solve the linear inequality 7 - 3s ≥ 1 using algebraic techniques. This problem highlights key concepts in solving inequalities, including the importance of flipping the inequality sign when dividing by negative numbers. Ideal for students in Grades 6-8.

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