To solve the inequality \(3a - 2 \geq 8\), follow these steps:

1. **Add 2 to both sides** of the inequality to isolate the term with \(a\):
   \[
   3a - 2 + 2 \geq 8 + 2
   \]
   \[
   3a \geq 10
   \]

2. **Divide both sides by 3** to solve for \(a\):
   \[
   a \geq \frac{10}{3}
   \]
   \[
   a \geq 3.33\overline{3}
   \]

So, the solution to the inequality is:
\[
a \geq \frac{10}{3}
\]

Would you like any further details or clarification on this process?

Here are some related questions you can try:
1. Solve \(4x + 5 \leq 3x + 12\).
2. Solve \(2b - 7 > 9\).
3. Solve \(5y + 3 < 12\).
4. Solve \(\frac{a}{2} - 4 \geq 1\).
5. Solve \(3p + 6 > 15\).

**Tip:** Always perform the same operation on both sides of an inequality to keep it balanced.

Learn how to solve the linear inequality 3a - 2 ≥ 8 with step-by-step instructions. This solution explores key algebraic techniques such as transposition and division in inequality solving. Suitable for students in Grades 7-8.

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