8z≤9z−5
         or         3−3z>30
Step 2 of 4 :  Solve the second inequality and express your answer in interval notation. Use decimal form for numerical values.

Let's focus on solving the second inequality step by step:

### Second Inequality:  
\[ 3 - 3z > 30 \]

#### Step 1: Subtract 3 from both sides
\[
-3z > 30 - 3
\]
\[
-3z > 27
\]

#### Step 2: Divide both sides by \(-3\)  
Remember, when dividing by a negative number, the inequality sign flips:
\[
z < \frac{27}{-3}
\]
\[
z < -9
\]

### Solution in Interval Notation:
The solution is:
\[
(-\infty, -9)
\]

Would you like details on the first inequality or have any other questions?

Here are some related questions:
1. How do you solve inequalities involving absolute values?
2. How do you solve compound inequalities?
3. What happens when dividing or multiplying inequalities by negative numbers?
4. Can inequalities have more than one solution?
5. How do you graph the solution of an inequality on a number line?

**Tip:** Always remember to flip the inequality sign when multiplying or dividing by a negative number.

Solve the second inequality and express your answer in interval notation. Use decimal form for numerical values: 3 - 3z > 30

Learn how to solve the inequality 3 - 3z > 30 step by step. This problem involves the algebraic concept of solving linear inequalities and expresses the solution in interval notation. Suitable for students in Grades 7-10.

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