Let's solve the inequality:

\[
\frac{1}{3}x - 2 \leq 4
\]

### Step 1: Eliminate the constant term on the left-hand side by adding 2 to both sides:

\[
\frac{1}{3}x - 2 + 2 \leq 4 + 2
\]

\[
\frac{1}{3}x \leq 6
\]

### Step 2: Multiply both sides of the inequality by 3 to eliminate the fraction:

\[
3 \times \frac{1}{3}x \leq 3 \times 6
\]

\[
x \leq 18
\]

### Final solution:
\[
x \leq 18
\]

This is the solution to the inequality.

Would you like any further details or clarifications?

Here are 5 related questions:
1. How do you solve a similar inequality with different fractions?
2. What happens if the inequality has a negative coefficient?
3. How do you graph the solution of this inequality on a number line?
4. Can you solve a compound inequality like \(\frac{1}{2}x + 1 \geq 3\) and \(x - 4 \leq 7\)?
5. How do you solve an inequality involving absolute values?

**Tip:** When multiplying or dividing an inequality by a negative number, remember to reverse the inequality sign.

Learn how to solve the linear inequality 1/3x - 2 ≤ 4 with a detailed step-by-step solution. This problem demonstrates key algebraic techniques such as isolating variables and multiplying inequalities. Suitable for students in Grades 6-8.

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