Math Problem Statement

Solve the equations.

Solution

Let's solve each equation step by step.

a) 2z55z=7+3z32z - 5 - 5z = 7 + 3z - 3

  1. Combine like terms on both sides: (2z5z)5=(3z+73)(2z - 5z) - 5 = (3z + 7 - 3) 3z5=3z+4-3z - 5 = 3z + 4

  2. Move all terms involving zz to one side: 3z3z=4+5-3z - 3z = 4 + 5 6z=9-6z = 9

  3. Solve for zz: z=96=32z = \frac{9}{-6} = -\frac{3}{2}

Thus, z=32z = -\frac{3}{2}.


b) 3(x+15)=12x73 \left( x + \frac{1}{5} \right) = \frac{1}{2}x - 7

  1. Distribute the 3 on the left-hand side: 3x+35=12x73x + \frac{3}{5} = \frac{1}{2}x - 7

  2. Multiply through by 10 (to eliminate fractions): 10(3x+35)=10(12x7)10 \left( 3x + \frac{3}{5} \right) = 10 \left( \frac{1}{2}x - 7 \right) 30x+6=5x7030x + 6 = 5x - 70

  3. Move the xx-terms to one side: 30x5x=70630x - 5x = -70 - 6 25x=7625x = -76

  4. Solve for xx: x=7625x = \frac{-76}{25}

Thus, x=7625x = \frac{-76}{25}.


c) 3(2m)=5m3(2 - m) = 5m

  1. Distribute the 3: 63m=5m6 - 3m = 5m

  2. Move all mm-terms to one side: 6=5m+3m6 = 5m + 3m 6=8m6 = 8m

  3. Solve for mm: m=68=34m = \frac{6}{8} = \frac{3}{4}

Thus, m=34m = \frac{3}{4}.


d) 0.05(t+3)=0.09+0.13t40.05(t + 3) = -0.09 + 0.13t - 4

  1. Distribute the 0.050.05 on the left-hand side: 0.05t+0.15=0.09+0.13t40.05t + 0.15 = -0.09 + 0.13t - 4

  2. Combine constants on the right-hand side: 0.05t+0.15=0.13t4.090.05t + 0.15 = 0.13t - 4.09

  3. Move all tt-terms to one side: 0.05t0.13t=4.090.150.05t - 0.13t = -4.09 - 0.15 0.08t=4.24-0.08t = -4.24

  4. Solve for tt: t=4.240.08=53t = \frac{-4.24}{-0.08} = 53

Thus, t=53t = 53.


Would you like any further details on any of the steps? Here are 5 related questions:

  1. How do you handle equations with variables on both sides?
  2. What is the best method to simplify fractions during equation solving?
  3. How can you verify your solutions to these types of equations?
  4. What are strategies for solving equations with decimals?
  5. What are common mistakes to avoid when solving linear equations?

Tip: When dealing with fractions, it can be helpful to multiply through by the least common denominator to eliminate them early on.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Fractions
Decimals

Formulas

Solving Linear equations: ax + b = 0
Solving equations with fractions: a/b = c/d
Solving equations with decimals: a.x + b = c

Theorems

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Suitable Grade Level

Middle School