Let's solve the two equations visible in the image:

Problem 7

Given: $5m - 1 = 4m + 5$

Solution:

1. Move all terms involving $m$ to one side of the equation: $5m - 4m = 5 + 1$
2. Simplify: $m = 6$

So, the solution is $m = 6$.

Problem 10

Given: $7t + 3 = 8 + 7t$

Solution:

1. Move all terms involving $t$ to one side of the equation and constants to the other: $7t - 7t = 8 - 3$
2. This simplifies to: $0 = 5$

Since this statement is false, there is no solution for this equation. The equation is inconsistent.

Would you like more detailed steps or have any questions?

Here are five related questions to consider:

1. How do you check if an equation has no solutions or infinitely many solutions?
2. What is the method for solving equations with variables on both sides?
3. Can equations with different coefficients for variables have a solution?
4. What happens when all variable terms cancel out in an equation?
5. How can you use substitution to verify solutions?

Tip: Always simplify and isolate variables step-by-step to avoid mistakes in algebraic equations.