https://file.aiquickdraw.com/mathbot/file/1727205002653puzut97p.jpg

The equation presented in the image is:

\[
0 = \frac{z + 3}{2}
\]

### To solve for \( z \):

1. **Multiply both sides by 2** to eliminate the denominator:
   \[
   0 \times 2 = z + 3 \implies 0 = z + 3
   \]

2. **Subtract 3 from both sides**:
   \[
   z = -3
   \]

Thus, the solution is:
\[
z = -3
\]

Would you like a more detailed explanation or have any additional questions?

Here are 5 related questions to practice:

1. Solve \( 0 = \frac{z + 5}{4} \).
2. Solve \( 0 = \frac{z - 2}{3} \).
3. Solve \( 0 = \frac{2z + 6}{5} \).
4. Solve \( 0 = \frac{z}{6} + 1 \).
5. Solve \( 0 = \frac{3z + 9}{7} \).

**Tip:** When solving linear equations with fractions, multiply both sides by the denominator to clear the fraction first!

Learn how to solve the linear equation 0 = (z + 3) / 2 by eliminating fractions and isolating z. This problem demonstrates key concepts in algebra and is suitable for students in Grades 6-8.

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