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It appears that you uploaded an image containing a mathematical problem. Let me analyze the content.

The problem seems to be about solving an equation, with step-by-step instructions for solving it. Here's what I can extract from the image:

**Problem:**  
Solve \( x + 7 = 7x - 6 \)

### Steps (from the image):
1. **b.** Perform the step to have variables (circles) on only one side.
2. **c.** Write the resulting step.
3. **d.** Perform the step to have variables (circles) alone on one side.
4. **e.** Write the resulting step.
5. **1.** Divide the variables (circles) and numbers (squares) into equal groups.
6. **2.** Show the value of one group.

### Now, let's go through the steps to solve this equation:

1. **Equation:**  
   \[
   x + 7 = 7x - 6
   \]

2. **Step b:**  
   Move all variables (x terms) to one side.  
   Subtract \( x \) from both sides:  
   \[
   7 = 6x - 6
   \]

3. **Step c:**  
   The resulting step is:  
   \[
   7 = 6x - 6
   \]

4. **Step d:**  
   Move the constant terms to the other side by adding 6 to both sides:  
   \[
   13 = 6x
   \]

5. **Step e:**  
   The resulting equation is:  
   \[
   13 = 6x
   \]

6. **Step 1:**  
   Divide both sides by 6 to solve for \( x \):  
   \[
   x = \frac{13}{6}
   \]

7. **Step 2:**  
   The value of one group (or the solution) is \( x = \frac{13}{6} \).

---

Would you like further clarification on any of these steps or details? Here are 5 follow-up questions to consider:

1. Why did we subtract \( x \) from both sides in Step b?
2. How do we know when to move constants to the other side of the equation?
3. What does it mean to "divide the variables and numbers into equal groups"?
4. Can the value of \( x = \frac{13}{6} \) be simplified further?
5. Why is it important to check the solution by substituting \( x = \frac{13}{6} \) back into the original equation?

**Tip:** Always remember that balancing an equation involves performing the same operation on both sides to maintain equality.

Step-by-step guide to solve the linear equation x + 7 = 7x - 6. Learn algebraic manipulation techniques, moving terms, and isolating variables. Suitable for Grades 6-8.

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