Let's solve the equation:

\[
\frac{x}{2} + \frac{3}{1} = \frac{x}{3}
\]

### Step 1: Simplify the equation

The equation can be rewritten as:

\[
\frac{x}{2} + 3 = \frac{x}{3}
\]

### Step 2: Eliminate the fractions

Multiply every term by the least common denominator (LCD) of 2 and 3, which is 6, to eliminate the fractions.

\[
6 \times \left( \frac{x}{2} + 3 = \frac{x}{3} \right)
\]

This results in:

\[
3x + 18 = 2x
\]

### Step 3: Solve for \( x \)

Subtract \( 2x \) from both sides to isolate \( x \):

\[
3x - 2x + 18 = 2x - 2x
\]
\[
x + 18 = 0
\]

Now subtract 18 from both sides:

\[
x = -18
\]

### Final Answer: 
\[
x = -18
\]

Would you like further details or have any questions?

Here are 5 related questions to explore:
1. What happens if there are more terms with fractions in an equation?
2. How do you solve equations with variables on both sides?
3. Can you explain how to find the least common denominator in a system of equations?
4. What if the equation had decimal coefficients instead of fractions?
5. How can we check if the solution is correct by substitution?

**Tip:** Always simplify an equation as much as possible before solving for the unknown variable to avoid unnecessary complications.

Learn how to solve the linear equation x/2 + 3 = x/3 using algebraic techniques. This step-by-step guide shows how to eliminate fractions and solve for x, covering key algebra concepts suitable for students in Grades 6-8.

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