https://file.aiquickdraw.com/mathbot/file/172676413627278ucb626.jpg

The equation in the image is:

\[
\frac{x}{3} + 19 = 24
\]

To solve for \(x\), follow these steps:

1. Subtract 19 from both sides to isolate the term involving \(x\):
   \[
   \frac{x}{3} = 24 - 19
   \]
   \[
   \frac{x}{3} = 5
   \]

2. Multiply both sides by 3 to solve for \(x\):
   \[
   x = 5 \times 3
   \]
   \[
   x = 15
   \]

Thus, the solution is \(x = 15\).

Would you like more details or have any other questions?

Here are 5 related questions to deepen your understanding:
1. How would you solve \(\frac{x}{5} + 7 = 12\)?
2. What if the equation was \(\frac{2x}{3} + 19 = 24\)?
3. How can you check if the solution to \(\frac{x}{3} + 19 = 24\) is correct?
4. How do you solve equations with variables on both sides, like \(\frac{x}{3} + 19 = \frac{2x}{5}\)?
5. What happens when fractions have different denominators in an equation?

**Tip:** Always perform inverse operations in algebra to isolate the variable efficiently!

Learn how to solve the linear equation x/3 + 19 = 24 with a clear step-by-step explanation. This problem covers key algebraic concepts including isolating the variable and inverse operations. Suitable for students in Grades 6-8.

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