Wendy solve the equation and found x to be 5. Which equation could she have solved? 

13−4x = 20

2x+4 = 12

3x−10 = 5x+20

14+2x = 54−6x

Let's solve each equation and determine which one gives \( x = 5 \) as the solution.

### 1. \( 13 - 4x = 20 \)
\[
13 - 4x = 20 \quad \Rightarrow \quad -4x = 20 - 13 \quad \Rightarrow \quad -4x = 7
\]
\[
x = \frac{7}{-4} = -\frac{7}{4}
\]
This does not give \( x = 5 \).

---

### 2. \( 2x + 4 = 12 \)
\[
2x + 4 = 12 \quad \Rightarrow \quad 2x = 12 - 4 \quad \Rightarrow \quad 2x = 8
\]
\[
x = \frac{8}{2} = 4
\]
This does not give \( x = 5 \).

---

### 3. \( 3x - 10 = 5x + 20 \)
\[
3x - 10 = 5x + 20 \quad \Rightarrow \quad 3x - 5x = 20 + 10 \quad \Rightarrow \quad -2x = 30
\]
\[
x = \frac{30}{-2} = -15
\]
This does not give \( x = 5 \).

---

### 4. \( 14 + 2x = 54 - 6x \)
\[
14 + 2x = 54 - 6x \quad \Rightarrow \quad 2x + 6x = 54 - 14 \quad \Rightarrow \quad 8x = 40
\]
\[
x = \frac{40}{8} = 5
\]
This equation gives \( x = 5 \).

---

### Conclusion:
The equation Wendy could have solved is \( 14 + 2x = 54 - 6x \).

---

Do you want more details or have any questions?

### Related Questions:
1. How do you solve linear equations with variables on both sides?
2. What happens if there are no solutions to a linear equation?
3. How can you verify your solution after solving an equation?
4. What are some common mistakes when solving linear equations?
5. How can you solve more complex equations involving fractions?

**Tip:** Always check your solution by substituting the value of \( x \) back into the original equation to ensure it satisfies both sides.

Wendy solve the equation and found x to be 5. Which equation could she have solved? 13−4x = 20 2x+4 = 12 3x−10 = 5x+20 14+2x = 54−6x

Discover how Wendy solved the linear equation to find x = 5. This problem involves solving equations with variables on both sides, simplifying algebraic expressions, and applying the properties of equality. Suitable for students in Grades 7-9.

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