The equation you provided is:

\[
D + g = 4ha
\]

This equation is a simple linear equation where \( D \), \( g \), and \( a \) are variables, and \( 4ha \) is the product of \( 4 \), \( h \), and \( a \).

If you want to solve for one of the variables, you can rearrange the equation accordingly. Here are a few examples:

1. **Solve for \( D \)**:
   \[
   D = 4ha - g
   \]

2. **Solve for \( g \)**:
   \[
   g = 4ha - D
   \]

3. **Solve for \( a \)** (assuming \( a \) is not zero):
   \[
   a = \frac{D + g}{4h}
   \]

This is a general equation, so the solution depends on the specific values you have for the variables.

Would you like more details or have any questions?

Here are five related questions that expand on this topic:
1. What happens if \( h \) is zero in this equation?
2. How would you solve the equation if \( D \), \( g \), and \( a \) are known, and you need to find \( h \)?
3. Can you factorize the equation further?
4. What would the equation look like if it were solved for \( h \)?
5. How would you graph this equation if \( D \) and \( g \) were plotted against \( a \)?

**Tip:** When solving for a variable, always check if it can be zero, as it may affect the equation's outcome (e.g., division by zero).

The query submitted by the user: D + g = 4ha for a

Learn how to solve the linear equation D + g = 4ha for the variable a. This detailed guide walks through different solutions and rearrangements for D, g, and a. Suitable for students in Grades 9-10, this explanation covers core algebraic concepts and formulas.

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