Let's solve the equation \(-8y + 2(y + 8) = -20\).

### Step 1: Distribute the 2 on the left side
\[
-8y + 2(y + 8) = -20
\]
Distribute the 2:
\[
-8y + 2y + 16 = -20
\]

### Step 2: Combine like terms
\[
(-8y + 2y) + 16 = -20
\]
\[
-6y + 16 = -20
\]

### Step 3: Subtract 16 from both sides
\[
-6y = -20 - 16
\]
\[
-6y = -36
\]

### Step 4: Divide both sides by -6
\[
y = \frac{-36}{-6}
\]
\[
y = 6
\]

So, the solution is \( y = 6 \).

Would you like more details or have any questions?

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Here are 5 related questions to deepen your understanding:

1. How would the solution change if the equation was \(-8y + 2(y + 8) = -10\)?
2. Can you solve the equation \(-6x + 3(x + 4) = -12\)?
3. What happens if you introduce more variables, like \(-8y + 2(y + z + 8) = -20\)?
4. How do you solve the equation if a fraction is involved, such as \(-8y + 2(y + 8) = -20\) but one term includes a fraction?
5. How would you check your solution for \(y = 6\) by substituting it back into the original equation?

**Tip:** Always distribute before combining like terms to simplify the equation.

Learn how to solve the linear equation -8y + 2(y + 8) = -20 step-by-step. This problem involves algebraic concepts such as the distributive property and combining like terms. Suitable for students in Grades 6-8.

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