To solve the equation \( 8x - 6y = -48 \) for one variable in terms of the other, let's rearrange the equation:

### Solve for \( x \):
1. Start by isolating \( x \) on one side of the equation:
   \[
   8x = 6y - 48
   \]
2. Divide both sides by 8 to solve for \( x \):
   \[
   x = \frac{6y - 48}{8}
   \]
   Simplify the expression:
   \[
   x = \frac{6y}{8} - \frac{48}{8}
   \]
   \[
   x = \frac{3y}{4} - 6
   \]

So, \( x = \frac{3y}{4} - 6 \).

### Solve for \( y \):
Alternatively, if you want to solve for \( y \):
1. Start by isolating \( y \):
   \[
   -6y = -8x - 48
   \]
2. Divide by -6 to solve for \( y \):
   \[
   y = \frac{-8x - 48}{-6}
   \]
   Simplify the expression:
   \[
   y = \frac{8x}{6} + \frac{48}{6}
   \]
   \[
   y = \frac{4x}{3} + 8
   \]

So, \( y = \frac{4x}{3} + 8 \).

Would you like more details, or do you have any questions?

Here are 5 related questions:
1. What is the graph of \( 8x - 6y = -48 \)?
2. Can we find the intercepts of this equation?
3. How can we rewrite this equation in slope-intercept form?
4. What happens when we substitute specific values for \( x \) or \( y \)?
5. How would this equation change if there were different constants?

**Tip:** When solving equations, isolating one variable helps simplify the problem, especially in systems of equations!

Learn how to solve the linear equation 8x - 6y = -48 by isolating x or y in terms of the other variable. This solution covers key algebraic concepts, such as linear equations, solving for variables, and simplifying expressions. Ideal for students in Grades 7-9.

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