The equation you provided is:

\[
8x - 3y = 72
\]

To solve this equation for either \(x\) or \(y\), you can isolate one of the variables. Let's solve for \(y\) in terms of \(x\):

1. Start with the given equation:
   \[
   8x - 3y = 72
   \]

2. Subtract \(8x\) from both sides:
   \[
   -3y = 72 - 8x
   \]

3. Divide both sides by \(-3\) to solve for \(y\):
   \[
   y = \frac{72 - 8x}{-3}
   \]

4. Simplify the expression:
   \[
   y = \frac{72}{-3} - \frac{8x}{-3}
   \]
   \[
   y = -24 + \frac{8x}{3}
   \]

So, the equation for \(y\) in terms of \(x\) is:
\[
y = \frac{8x}{3} - 24
\]

Would you like to explore this further or have more details?

### Related Questions:
1. How do you find the slope and intercept from the equation?
2. How do you graph the equation after solving for \(y\)?
3. Can you solve for \(x\) instead of \(y\)?
4. What happens when \(x = 0\) or \(y = 0\)?
5. How can you convert this to a standard form for linear equations?

**Tip:** When solving linear equations, isolating one variable makes it easier to graph or find specific solutions!

Learn how to solve the linear equation 8x - 3y = 72 by isolating the variable y. This problem demonstrates core algebraic concepts, including manipulating linear equations and solving for variables. Suitable for students in Grades 7-10.

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