To solve the equation \(8x + 3 = -13\), follow these steps:

1. **Subtract 3 from both sides** to isolate the term with \(x\) on one side of the equation:
   \[
   8x + 3 - 3 = -13 - 3
   \]
   Simplifying this, we get:
   \[
   8x = -16
   \]

2. **Divide both sides by 8** to solve for \(x\):
   \[
   x = \frac{-16}{8}
   \]
   Simplifying this, we get:
   \[
   x = -2
   \]

So, the solution is \(x = -2\).

Would you like more details on any step, or do you have any other questions? Here are some related questions to consider:

1. How would you solve \(10x + 5 = -25\)?
2. What happens if you have \(8x + 3 = -13\) and you want to isolate \(x\) by adding first?
3. How do you solve the equation \(7x - 4 = 10\)?
4. Can you solve for \(x\) in the equation \(9x + 2 = 20\)?
5. How would you approach solving \(5x + 3 = 8x - 7\)?

**Tip:** Always perform the same operation on both sides of the equation to maintain equality.

Learn how to solve the linear equation 8x + 3 = -13 with a clear, step-by-step solution. This problem demonstrates essential algebraic concepts, including isolating variables and simplifying equations. Suitable for students in Grades 6-8.

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