Let's solve the equation:

\[
63 = 6 - (-10a + 3)
\]

### Step 1: Simplify the right-hand side
Distribute the negative sign inside the parentheses:

\[
63 = 6 + 10a - 3
\]

### Step 2: Combine like terms on the right-hand side
\[
63 = (6 - 3) + 10a
\]
\[
63 = 3 + 10a
\]

### Step 3: Isolate the variable term
Subtract 3 from both sides:

\[
63 - 3 = 10a
\]
\[
60 = 10a
\]

### Step 4: Solve for \( a \)
Divide both sides by 10:

\[
a = \frac{60}{10}
\]
\[
a = 6
\]

Thus, the solution is \( a = 6 \).

Do you want more details on any step? 

Here are some related questions:
1. How do you solve equations involving parentheses and distribution?
2. What is the importance of combining like terms in algebra?
3. Can equations always be solved in 4 steps like this one?
4. How would the solution change if the equation involved fractions?
5. How can solving equations help in real-life situations?

**Tip:** Always check your solution by substituting it back into the original equation to verify your answer.

Learn how to solve the linear equation 63 = 6 - (-10a + 3) step by step. This problem covers important algebraic concepts like distribution, combining like terms, and isolating variables. Suitable for students in Grades 6-8.

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