Let's solve the equation \( 3\left(q + \dfrac{4}{3}\right) = 2 \).

### Step 1: Distribute the 3
Distribute the \(3\) to both terms inside the parentheses:
\[
3 \times q + 3 \times \dfrac{4}{3} = 2
\]
\[
3q + 4 = 2
\]

### Step 2: Isolate the variable \(q\)
Subtract 4 from both sides:
\[
3q = 2 - 4
\]
\[
3q = -2
\]

### Step 3: Solve for \(q\)
Divide both sides by 3 to solve for \(q\):
\[
q = \dfrac{-2}{3}
\]

Thus, the solution is:
\[
q = -\dfrac{2}{3}
\]

Would you like more details or have any questions?

Here are five related questions to deepen your understanding:
1. How would the solution change if the equation were \( 3\left(q + \dfrac{4}{3}\right) = 5 \)?
2. How do you solve a similar equation with different denominators inside the parentheses?
3. What if you had to solve \( 5\left(q + \dfrac{3}{5}\right) = 1 \)?
4. Can you explain how distributing works when the coefficient outside is negative?
5. How would you check if the solution \( q = -\dfrac{2}{3} \) is correct?

**Tip:** Always distribute multiplication across both terms inside parentheses before moving on to other steps.

Explore how to solve the linear equation 3(q + 4/3) = 2 with a detailed step-by-step guide. This tutorial covers key algebra concepts, including the distributive property and isolating the variable, suitable for Grades 6-8.

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