Let's solve the equation:

\[
35 - 5(p - 1) = 5
\]

### Step 1: Distribute the \(-5\) across \((p - 1)\)

\[
35 - 5p + 5 = 5
\]

### Step 2: Combine like terms on the left-hand side

\[
(35 + 5) - 5p = 5
\]
\[
40 - 5p = 5
\]

### Step 3: Isolate the term with \(p\)

Subtract 40 from both sides:

\[
-5p = 5 - 40
\]
\[
-5p = -35
\]

### Step 4: Solve for \(p\)

Divide both sides by \(-5\):

\[
p = \frac{-35}{-5}
\]
\[
p = 7
\]

### Final Answer: 
\[
p = 7
\]

Would you like further clarification or more details on any step?

Here are 5 related questions:
1. How do you solve linear equations with parentheses?
2. What are like terms, and how do you combine them?
3. How can you check if your solution to an equation is correct?
4. What are distributive properties in algebra?
5. How can equations with variables on both sides be solved?

**Tip:** Always double-check your solution by substituting it back into the original equation!

Discover how to solve the linear equation 35 - 5(p - 1) = 5 with a detailed solution. Learn to apply the distributive property, combine like terms, and isolate variables. Ideal for students in Grades 6-8 looking to strengthen their algebra skills.

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