Let's solve the equation \(30 = 8x + 3 - 5x\):

### Step 1: Simplify the terms on the right-hand side
Combine like terms:
\[
8x - 5x + 3 = 3x + 3
\]
So the equation becomes:
\[
30 = 3x + 3
\]

### Step 2: Isolate the variable \(x\)
Subtract 3 from both sides:
\[
30 - 3 = 3x
\]
\[
27 = 3x
\]

### Step 3: Solve for \(x\)
Divide both sides by 3:
\[
x = \frac{27}{3} = 9
\]

Thus, the solution is \(x = 9\).

Would you like more details or have any questions?

Here are 5 related questions you can explore:
1. What happens if we substitute \(x = 9\) back into the original equation?
2. How would the solution change if the equation was \(30 = 8x + 5 - 5x\)?
3. Can you solve \(40 = 6x + 10 - 4x\) using a similar method?
4. How do you solve equations with fractions, like \(30 = \frac{8}{2}x + 3 - 5x\)?
5. What if there were more variables on both sides of the equation?

**Tip**: Always combine like terms first to simplify your equation, which makes the problem easier to solve!

This guide walks you through solving the linear equation 30 = 8x + 3 - 5x, covering algebraic concepts like combining like terms and simplifying equations. Perfect for students in Grades 6-8 looking to strengthen their algebra skills.

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