Let's solve the equation step by step:

The equation is:
\[
3(2x + 5) + x = 35
\]

### Step 1: Distribute the 3 on the left side
\[
3 \times 2x + 3 \times 5 + x = 35
\]
\[
6x + 15 + x = 35
\]

### Step 2: Combine like terms
\[
6x + x + 15 = 35
\]
\[
7x + 15 = 35
\]

### Step 3: Subtract 15 from both sides
\[
7x = 35 - 15
\]
\[
7x = 20
\]

### Step 4: Divide by 7
\[
x = \frac{20}{7}
\]
\[
x = \frac{20}{7} \approx 2.86
\]

Thus, the solution is \( x = \frac{20}{7} \).

Would you like more details or further explanations?

Here are 5 related questions for practice:
1. Solve \( 2(3x + 4) + 5x = 24 \).
2. Solve \( 4x + 7 = 3x + 15 \).
3. Simplify and solve \( 5(2x + 1) - 4x = 19 \).
4. Solve \( 6x - 2 = 3x + 4 \).
5. Expand and simplify \( 2(4x + 3) - 3(2x - 5) \).

**Tip:** Always distribute and combine like terms first when solving linear equations!

Learn how to solve the linear equation 3(2x + 5) + x = 35 with a step-by-step breakdown. This problem demonstrates algebraic concepts such as the distributive property and combining like terms, suitable for students in Grades 6-8.

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