Let's solve the equation \( 2(x + 2) = -8 \).

### Step-by-step solution:

1. Distribute the 2 on the left side:
   \[
   2(x + 2) = 2x + 4
   \]
   So the equation becomes:
   \[
   2x + 4 = -8
   \]

2. Subtract 4 from both sides to isolate the term with \( x \):
   \[
   2x + 4 - 4 = -8 - 4
   \]
   Simplifying:
   \[
   2x = -12
   \]

3. Divide both sides by 2 to solve for \( x \):
   \[
   \frac{2x}{2} = \frac{-12}{2}
   \]
   Simplifying:
   \[
   x = -6
   \]

### Final Answer:
\[
x = -6
\]

Would you like further details on any step or have any questions?

Here are 5 related questions to explore:

1. How do you solve equations with fractions like \( \frac{3(x+4)}{2} = 6 \)?
2. What happens when you have more than one variable, like in \( 3x + 2y = 12 \)?
3. How do you solve equations with exponents, such as \( 2(x+2)^2 = 8 \)?
4. What methods are used to solve quadratic equations, like \( x^2 - 4x - 12 = 0 \)?
5. How can you solve systems of equations with two variables, like \( 2x + y = 10 \) and \( 3x - y = 5 \)?

**Tip**: Always check your solution by plugging it back into the original equation to verify it satisfies the equation.

This webpage provides a step-by-step solution for the linear equation 2(x + 2) = -8. It covers key algebraic concepts such as the distributive property and properties of equality, making it suitable for students in Grades 6-8.

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