Let's solve the equation step by step:

\[
2x + 1 - 20 = 8x + 5
\]

### Step 1: Simplify both sides.
First, simplify the left side by combining like terms:
\[
2x - 19 = 8x + 5
\]

### Step 2: Move the terms involving \(x\) to one side.
Subtract \(2x\) from both sides:
\[
-19 = 6x + 5
\]

### Step 3: Isolate the term with \(x\).
Subtract 5 from both sides:
\[
-24 = 6x
\]

### Step 4: Solve for \(x\).
Divide both sides by 6:
\[
x = -4
\]

So, the solution to the equation is:

\[
x = -4
\]

Would you like more details or have any questions?

### Related Questions:
1. How can you check if \(x = -4\) is the correct solution?
2. What are the properties of equations that allow moving terms across sides?
3. Can you solve a similar equation where variables appear on both sides?
4. What happens if there's no solution or infinite solutions to an equation?
5. How would the equation change if the constants were different?

### Tip:
Always verify your solution by substituting it back into the original equation.

Learn how to solve the linear equation 2x + 1 - 20 = 8x + 5 with a detailed, step-by-step solution. This problem covers key algebraic concepts like simplification, moving terms, and solving for x. Ideal for students in Grades 6-8.

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