You provided the equation:

$-2x + 5y = 3$

To solve for one of the variables, we'll need another equation for a system of linear equations, or you can specify whether you'd like to isolate $x$ or $y$. Here's how we can proceed:

1. Solving for $x$: We can isolate $x$ in terms of $y$. $-2x = 3 - 5y$ $x = \frac{5y - 3}{2}$

2. Solving for $y$: We can isolate $y$ in terms of $x$. $5y = 2x + 3$ $y = \frac{2x + 3}{5}$

If you need to find a specific solution, we'd need a second equation. Would you like to proceed with that, or would you like to explore another part of this equation?

Follow-up questions:

1. How would you solve a system of linear equations?
2. What does the slope-intercept form of a linear equation look like?
3. How can we graph this equation?
4. How would you solve for $x$ and $y$ if you had another equation in the system?
5. What is the geometric interpretation of this equation?

Tip: Remember that when you have just one equation with two variables, you cannot solve for both unless there's additional information (such as a second equation in a system).