Let's solve the equation step by step:

\[
20 + 5.50h = 15 + 6.50h
\]

### Step 1: Subtract \(5.50h\) from both sides
\[
20 = 15 + (6.50h - 5.50h)
\]

Simplifying the terms with \(h\):
\[
20 = 15 + 1h
\]
Which is:
\[
20 = 15 + h
\]

### Step 2: Subtract 15 from both sides
\[
20 - 15 = h
\]
\[
h = 5
\]

So, the solution is \(h = 5\).

Would you like further clarification or additional details?

Here are five related questions to extend your learning:

1. How do you solve linear equations with variables on both sides?
2. What is the significance of isolating the variable in an equation?
3. How do you check if the solution to an equation is correct?
4. How does adding or subtracting terms affect both sides of an equation?
5. What happens when the variable has a coefficient greater than 1?

**Tip:** Always check your solution by substituting the value of the variable back into the original equation!

Learn how to solve the linear equation 20 + 5.50h = 15 + 6.50h with a detailed step-by-step solution. This problem involves key algebraic concepts, including isolating variables and balancing equations. Ideal for students in Grades 6-8.

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