To solve the equation \( 2(3 - 8y) = 0 \), follow these steps:

### Step 1: Distribute the 2 to both terms inside the parentheses.
\[
2 \times 3 = 6
\]
\[
2 \times (-8y) = -16y
\]
So the equation becomes:
\[
6 - 16y = 0
\]

### Step 2: Solve for \( y \).
- Subtract 6 from both sides:
\[
-16y = -6
\]
- Divide both sides by -16 to isolate \( y \):
\[
y = \frac{-6}{-16} = \frac{6}{16} = \frac{3}{8}
\]

### Final Answer:
\[
y = \frac{3}{8}
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you solve equations involving parentheses and distribution?
2. What are the steps to simplify fractions?
3. Can you solve \( 5(2y + 4) = 10 \)?
4. How do you solve equations with variables on both sides?
5. What happens if there are decimals or fractions inside parentheses?

**Tip:** Always distribute first before solving for the variable when parentheses are involved!

Learn how to solve the linear equation 2(3 - 8y) = 0 using the distributive property. This step-by-step solution demonstrates key algebraic concepts such as distributing constants and solving for variables. Suitable for students in Grades 6-8.

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