The inequality $x^2 > 0$ implies that the square of $x$ is greater than zero. Here are key points to consider:

1. When is $x^2 > 0$?
   For any real number $x$, $x^2$ (the square of $x$) is always non-negative. However, $x^2 > 0$ specifically excludes the case where $x = 0$. Thus, $x \neq 0$.

2. Solution to $x^2 > 0$:
   The inequality is true for all $x \in \mathbb{R} \setminus \{0\}$, meaning all real numbers except zero.

3. Graphical Representation:
   The parabola $y = x^2$ opens upwards and touches the $x$-axis at $x = 0$. The inequality $x^2 > 0$ holds for the regions where $y > 0$, which are $x < 0$ and $x > 0$.

Final Solution:

The solution is $x \in (-\infty, 0) \cup (0, \infty)$.

Would you like me to expand on the explanation or provide a graphical representation?

Related Questions:

1. What is the solution to $x^2 \geq 0$?
2. How does the inequality $x^2 > a^2$ differ from $x^2 > 0$?
3. Can $x^2 > 0$ hold for complex numbers?
4. How is $x^2 > 0$ related to the absolute value function?
5. What changes if the inequality is $x^2 < 0$?

Tip: Squaring any real number makes it non-negative, but inequalities involving squares often require analyzing specific cases separately.