We are given the inequality:

$-6x - 4 \leq -4$

To solve for $x$, let's follow these steps:

1. Add 4 to both sides of the inequality: $-6x - 4 + 4 \leq -4 + 4$ This simplifies to: $-6x \leq 0$

2. Divide both sides by -6 to isolate $x$. Since we're dividing by a negative number, we must reverse the inequality: $x \geq 0$

Thus, the solution is $x \geq 0$.

Now, let's check each of the given values of $x$ to see which one does not satisfy $x \geq 0$:

• A. $2.5$: $2.5 \geq 0$, so it satisfies the inequality.
• B. $0$: $0 \geq 0$, so it satisfies the inequality.
• C. $17$: $17 \geq 0$, so it satisfies the inequality.
• D. $-4$: $-4 \geq 0$ is false.

Thus, the value of $x$ that does not make the inequality true is:

D. −4

Would you like further details or have any questions?

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Here are 5 related questions to consider:

1. How do you reverse the inequality when dividing by a negative number?
2. What happens if you multiply both sides of an inequality by a negative number?
3. Can you provide an example of solving an inequality involving fractions?
4. How would you solve the inequality $3x + 5 > 2x - 7$?
5. What is the difference between solving equations and inequalities?

Tip: Always remember to reverse the inequality sign when multiplying or dividing both sides by a negative number.