To solve the inequality $2 < x + 5$, we need to isolate $x$:

1. Start by subtracting 5 from both sides: $2 - 5 < x + 5 - 5$ $-3 < x$

So, the inequality notation is: $x > -3$

To graph this on the number line, we would place an open circle at $-3$ (indicating that $-3$ is not included in the solution) and shade to the right to show all values greater than $-3$.

Would you like more details or have any other questions?

Here are five related questions to deepen your understanding:

1. How would the solution change if the original inequality were $2 \leq x + 5$?
2. How can you solve and graph the inequality $x + 5 > 7$?
3. What happens to the solution if we multiply both sides of an inequality by a negative number?
4. Can you solve a compound inequality, such as $1 < x + 4 < 6$?
5. How does graphing $x \geq -3$ differ from $x > -3$?

Tip: Always remember to reverse the inequality sign when you multiply or divide both sides by a negative number.