Math Problem Statement
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Solution
Let's solve the problem step by step.
The given geometric series is:
Part (a) - For which does the series converge?
A geometric series converges if the absolute value of the common ratio is less than 1:
First, identify the common ratio of the series. The first term is 2, and the second term is , so the common ratio is:
For the series to converge:
This simplifies to:
Therefore, the series converges for:
Part (b) - Can the sum of the series found in (a) be ?
To find the sum of a convergent geometric series, use the formula:
In this series, the first term is 2, and the common ratio is . Thus, the sum of the series is:
Simplify the denominator:
We need to determine if this sum can be :
Solve for :
However, from part (a), we know that the series converges only for . Since does not satisfy this condition, the series cannot have a sum of .
Summary
(a) The series converges for .
(b) The sum of the series cannot be since is outside the interval of convergence .
Do you have any questions or need further details on any part? Here are some related questions you might find interesting:
- What is the sum of the series when ?
- How does the sum change if the first term is different?
- What happens if the common ratio is greater than 1?
- Can the series be transformed into another form that is easier to sum?
- How would you represent the series if ?
- What are some real-world applications of geometric series?
- How would you check the convergence of a non-geometric series?
- What is the radius of convergence for a power series in general?
Tip: Always verify the conditions of convergence before attempting to find the sum of an infinite series.
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Math Problem Analysis
Mathematical Concepts
Geometric Series
Convergence Criteria
Summation of Series
Formulas
Geometric series sum formula: S = a / (1 - r)
Theorems
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Suitable Grade Level
Advanced High School