Math Problem Statement

Solve the following mathematical problems involving function compositions and function properties based on the given diagram and equations.

Solution

Let's work through the questions in the image step by step.

1. Diagram Functions

Given:

  • f:ABf: A \to B
  • g:BCg: B \to C

a. Compute (gf)(1),(gf)(2),(gf)(3),(g \circ f)(1), (g \circ f)(2), (g \circ f)(3), and (gf)(4)(g \circ f)(4).

To solve this, follow these steps:

  • First, evaluate f(x)f(x) for each value from set AA to set BB.
  • Then, use the output from f(x)f(x) as the input to g(x)g(x).

From the diagram:

  • f(1)=af(1) = a, f(2)=cf(2) = c, f(3)=bf(3) = b, f(4)=ef(4) = e
  • g(a)=pg(a) = p, g(b)=rg(b) = r, g(c)=qg(c) = q, g(e)=qg(e) = q

Thus:

  • (gf)(1)=g(f(1))=g(a)=p(g \circ f)(1) = g(f(1)) = g(a) = p
  • (gf)(2)=g(f(2))=g(c)=q(g \circ f)(2) = g(f(2)) = g(c) = q
  • (gf)(3)=g(f(3))=g(b)=r(g \circ f)(3) = g(f(3)) = g(b) = r
  • (gf)(4)=g(f(4))=g(e)=q(g \circ f)(4) = g(f(4)) = g(e) = q

b. Determine the domain and range of gfg \circ f.

  • Domain: The domain of gfg \circ f is the same as the domain of ff, which is A={1,2,3,4}A = \{1, 2, 3, 4\}.
  • Range: The range of gfg \circ f is the set of possible outputs from gfg \circ f, which are {p,q,r}\{p, q, r\}.

2. Composition of Functions

Now, let's move to the second part.

You are given four function pairs, and the task is to find fgf \circ g, gfg \circ f, and fgf \cdot g (likely the multiplication of functions). Let's look at the first one as an example:

a.

  • f(x)=x2+3f(x) = x^2 + 3
  • g(x)=x1g(x) = x - 1
  1. fg(x)=f(g(x))=f(x1)=(x1)2+3=x22x+1+3=x22x+4f \circ g(x) = f(g(x)) = f(x - 1) = (x - 1)^2 + 3 = x^2 - 2x + 1 + 3 = x^2 - 2x + 4
  2. gf(x)=g(f(x))=g(x2+3)=(x2+3)1=x2+2g \circ f(x) = g(f(x)) = g(x^2 + 3) = (x^2 + 3) - 1 = x^2 + 2
  3. fg(x)=f(x)g(x)=(x2+3)(x1)=x3x2+3x3f \cdot g(x) = f(x) \cdot g(x) = (x^2 + 3) \cdot (x - 1) = x^3 - x^2 + 3x - 3

3. Finding Functions for Compositions

You are tasked with determining two functions ff and gg such that fg(x)=h(x)f \circ g(x) = h(x).

a. Given h(x)=(2x+1)2h(x) = (2x + 1)^2, you can think of decomposing it as follows:

Let:

  • g(x)=2x+1g(x) = 2x + 1
  • f(x)=x2f(x) = x^2

Now check:

  • f(g(x))=f(2x+1)=(2x+1)2=h(x)f(g(x)) = f(2x + 1) = (2x + 1)^2 = h(x)

This means the functions f(x)=x2f(x) = x^2 and g(x)=2x+1g(x) = 2x + 1 satisfy fg(x)=h(x)f \circ g(x) = h(x).


Do you want more details on any specific question or further steps? Here are 5 questions to deepen your understanding:

  1. How do you determine the domain and range of a composed function?
  2. What is the difference between function composition and function multiplication?
  3. How do you decompose complex functions like in problem 3?
  4. How can the composition of two functions simplify expressions in calculus?
  5. What are the steps to find fgf \circ g for functions with square roots or fractions?

Tip: Always check the domain restrictions when composing functions, especially when dealing with square roots or fractions.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Domain and Range
Algebraic Manipulation
Quadratic Functions

Formulas

f(g(x)) = f(g(x))
Domain of composite functions
Range of composite functions
Algebraic expansions

Theorems

Function Composition Theorem
Properties of Domains and Ranges

Suitable Grade Level

Grades 10-12