To solve for $y$ in the equation $Ax + By = C$, follow these steps:

1. Start with the equation: $Ax + By = C$

2. Subtract $Ax$ from both sides to isolate the term with $y$: $By = C - Ax$

3. Now, divide both sides by $B$ to solve for $y$: $y = \frac{C - Ax}{B}$

Thus, the equation solved for $y$ is: $y = \frac{C - Ax}{B}$

Would you like more details on solving this, or do you have any questions?

Here are 5 related questions for further practice:

1. What is the value of $y$ if $A = 2$, $B = 3$, $C = 12$, and $x = 4$?
2. How would you graph $y = \frac{C - Ax}{B}$ for different values of $A$, $B$, and $C$?
3. How do you find the slope of the line represented by $y = \frac{C - Ax}{B}$?
4. How does changing the value of $B$ affect the graph of the equation?
5. What is the equation of the line in slope-intercept form when $A = 1$, $B = -2$, and $C = 5$?

Tip: The equation $y = \frac{C - Ax}{B}$ represents a straight line in the form $y = mx + b$, where $m = -\frac{A}{B}$ and $b = \frac{C}{B}$.