To solve for \( y \) in the equation \( Ax + By = C \), follow these steps:

1. Start with the equation:
   \[
   Ax + By = C
   \]

2. Subtract \( Ax \) from both sides to isolate the term with \( y \):
   \[
   By = C - Ax
   \]

3. Now, divide both sides by \( B \) to solve for \( y \):
   \[
   y = \frac{C - Ax}{B}
   \]
   
Thus, the equation solved for \( y \) is:
\[
y = \frac{C - Ax}{B}
\]

Would you like more details on solving this, or do you have any questions?

Here are 5 related questions for further practice:
1. What is the value of \( y \) if \( A = 2 \), \( B = 3 \), \( C = 12 \), and \( x = 4 \)?
2. How would you graph \( y = \frac{C - Ax}{B} \) for different values of \( A \), \( B \), and \( C \)?
3. How do you find the slope of the line represented by \( y = \frac{C - Ax}{B} \)?
4. How does changing the value of \( B \) affect the graph of the equation?
5. What is the equation of the line in slope-intercept form when \( A = 1 \), \( B = -2 \), and \( C = 5 \)?

**Tip:** The equation \( y = \frac{C - Ax}{B} \) represents a straight line in the form \( y = mx + b \), where \( m = -\frac{A}{B} \) and \( b = \frac{C}{B} \).

Learn how to solve for y in the linear equation Ax + By = C with a step-by-step breakdown. Understand core algebraic concepts such as linear equations and slope-intercept form. Perfect for students in Grades 8-10.

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