Math Problem Statement

In d = rt, solve for r. In I = Pr, solve for P.

Solution

Let's break down and solve the two equations provided in the image.

  1. In d=rtd = rt, solve for rr:

    The equation is d=rtd = rt, where:

    • dd is the distance,
    • rr is the rate (or speed),
    • tt is the time.

    To solve for rr, divide both sides of the equation by tt:

    r=dtr = \frac{d}{t}

  2. In I=PrI = Pr, solve for PP:

    The equation is I=PrI = Pr, where:

    • II is the current,
    • PP is some parameter (possibly power in some contexts),
    • rr is another variable (likely a rate or constant).

    To solve for PP, divide both sides of the equation by rr:

    P=IrP = \frac{I}{r}


Would you like further details or explanations on these steps?

Here are five related questions:

  1. How would you solve for tt in the equation d=rtd = rt?
  2. What happens if one of the variables in either equation equals zero?
  3. Can these equations be used for real-world applications? If so, how?
  4. How do you apply dimensional analysis to check if these equations are dimensionally consistent?
  5. What are other formulas involving rates that follow a similar structure?

Tip: When solving for a variable, always aim to isolate it by performing inverse operations on both sides of the equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Solving for a Variable
Linear Equations

Formulas

d = rt
I = Pr

Theorems

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Suitable Grade Level

Grades 6-8