https://file.aiquickdraw.com/mathbot/file/1728096253214p7a3hck0.jpg

The equation in the image is:

\[
t = v + u + s
\]

To solve for \( s \) in terms of \( t \), \( u \), and \( v \), we need to isolate \( s \) on one side of the equation. 

Starting from the original equation:

\[
t = v + u + s
\]

Subtract \( v \) and \( u \) from both sides:

\[
s = t - v - u
\]

Thus, the solution is:

\[
s = t - v - u
\]

Would you like further details or have any questions on this? 

Here are five related questions to consider:
1. What happens if you solve for \( v \) instead of \( s \)?
2. How would this equation change if it was in three dimensions with vectors?
3. Can you apply this equation to a physical context, such as velocity and displacement?
4. How would the solution change if there was a coefficient before \( s \)?
5. How could this formula be applied in a system of equations?

**Tip:** When solving for a variable, always perform the same operation on both sides of the equation to maintain equality.

Solve for s in terms of t, u, and v. The equation is t = v + u + s.

Learn how to solve for s in the equation t = v + u + s. This algebra problem focuses on isolating a variable using basic algebraic techniques, suitable for students in Grades 6-8.

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