Math Problem Statement

Solve the following equation for 𝑑1.

𝐴=𝑑1⋅𝑑2÷2

Choose all true answers.

Group of answer choices

𝑑1=2𝐴𝑑2

𝑑1=2𝐴𝑑2

𝑑1=2𝑑2𝐴

𝑑1=𝐴⋅𝑑2÷2

𝑑1=𝐴(2𝑑2)

Solution

Let's start by solving the given equation for d1d_1.

The equation is:

A=d1d22A = \frac{d_1 \cdot d_2}{2}

To solve for d1d_1, follow these steps:

  1. Multiply both sides of the equation by 2 to eliminate the denominator:

2A=d1d22A = d_1 \cdot d_2

  1. Divide both sides by d2d_2 to isolate d1d_1:

d1=2Ad2d_1 = \frac{2A}{d_2}

Now that we have the solution d1=2Ad2d_1 = \frac{2A}{d_2}, let's examine the provided choices.

  • Choice 1: d1=2Ad2d_1 = \frac{2A}{d_2} – This is correct.
  • Choice 2: d1=2Ad2d_1 = \frac{2A}{d_2} – This is a duplicate of Choice 1, so it is also correct.
  • Choice 3: d1=2d2Ad_1 = \frac{2d_2}{A} – This is incorrect. The correct formula has d2d_2 in the denominator, not the numerator.
  • Choice 4: d1=Ad22d_1 = \frac{A \cdot d_2}{2} – This is incorrect. The formula should have 2 in the numerator, not the denominator.
  • Choice 5: d1=A2d2d_1 = \frac{A}{2d_2} – This is incorrect. It does not match the correct formula.

Correct answers:

  • d1=2Ad2d_1 = \frac{2A}{d_2} (Choice 1 and Choice 2)

Would you like further details on this solution or have any questions?

Here are five related questions to expand your understanding:

  1. How would the equation change if the formula was A=d1d2A = d_1 \cdot d_2?
  2. Can you derive d2d_2 from the original equation in terms of AA and d1d_1?
  3. What happens if d2=0d_2 = 0? How does it affect the equation?
  4. What is the significance of multiplying both sides of an equation by a number?
  5. How can you verify that d1=2Ad2d_1 = \frac{2A}{d_2} is the correct solution?

Tip: Always check for extraneous solutions by substituting the values back into the original equation to ensure they satisfy the equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Solving Equations
Multiplication and Division

Formulas

A = (d1 ⋅ d2) ÷ 2
d1 = 2A / d2

Theorems

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Suitable Grade Level

Grades 8-10