Math Problem Statement

Solve the following exponential inequalities: 1) 3^(x+1) > 243, 2) 25^2 ≥ 5^(x+1), 3) (49/81)^(3x+1) ≥ 9/7, 4) (1/9)^(3x+5) ≤ (1/243)^(x-6)

Solution

Let's solve the given exponential inequalities one by one.

Problem 1: Solve 3x+1>2433^{x+1} > 243

Solution:

  1. Write 243 as a power of 3:
    243=35243 = 3^5

  2. Rewrite the inequality:
    3x+1>353^{x+1} > 3^5

  3. Since the bases are the same and the exponential function is strictly increasing, we can compare the exponents:
    x+1>5x + 1 > 5

  4. Solve for xx:
    x>4x > 4

Problem 2: Solve 2525x+125^2 \geq 5^{x+1}

Solution:

  1. Calculate 25225^2:
    25=52    252=(52)2=5425 = 5^2 \implies 25^2 = (5^2)^2 = 5^4

  2. Rewrite the inequality:
    545x+15^4 \geq 5^{x+1}

  3. Since the bases are the same, compare the exponents:
    4x+14 \geq x + 1

  4. Solve for xx:
    41x    x34 - 1 \geq x \implies x \leq 3

Problem 3: Solve (4981)3x+197\left(\frac{49}{81}\right)^{3x+1} \geq \frac{9}{7}

Solution:

  1. Rewrite the terms as powers of 7 and 9:
    4981=(79)2\frac{49}{81} = \left(\frac{7}{9}\right)^2
    97=(79)1\frac{9}{7} = \left(\frac{7}{9}\right)^{-1}

  2. Rewrite the inequality:
    ((79)2)3x+1(79)1\left(\left(\frac{7}{9}\right)^2\right)^{3x+1} \geq \left(\frac{7}{9}\right)^{-1}

  3. Simplify the left side:
    (79)2(3x+1)(79)1\left(\frac{7}{9}\right)^{2(3x+1)} \geq \left(\frac{7}{9}\right)^{-1}

  4. Since 79<1\frac{7}{9} < 1, reverse the inequality when comparing exponents:
    2(3x+1)12(3x+1) \leq -1

  5. Solve for xx:
    6x+216x + 2 \leq -1
    6x36x \leq -3
    x12x \leq -\frac{1}{2}

Problem 4: Solve (19)3x+5(1243)x6\left(\frac{1}{9}\right)^{3x+5} \leq \left(\frac{1}{243}\right)^{x-6}

Solution:

  1. Rewrite the bases as powers of 3:
    19=32\frac{1}{9} = 3^{-2}
    1243=35\frac{1}{243} = 3^{-5}

  2. Rewrite the inequality:
    (32)3x+5(35)x6(3^{-2})^{3x+5} \leq (3^{-5})^{x-6}

  3. Simplify the exponents:
    32(3x+5)35(x6)3^{-2(3x+5)} \leq 3^{-5(x-6)}

  4. Since the bases are the same and both sides have negative exponents (exponential function is decreasing), we can compare the exponents:
    2(3x+5)5(x6)-2(3x+5) \geq -5(x-6)

  5. Solve for xx:
    6x105x+30-6x - 10 \geq -5x + 30
    x40-x \geq 40
    x40x \leq -40

Summary of Solutions:

  1. x>4x > 4
  2. x3x \leq 3
  3. x12x \leq -\frac{1}{2}
  4. x40x \leq -40

Would you like more details or explanations for any of these steps?

Related Questions:

  1. How do you solve exponential equations involving different bases?
  2. What are some common techniques for solving inequalities?
  3. How can you convert a fraction to a power of a base?
  4. What happens to an inequality when you multiply or divide by a negative number?
  5. What is the importance of recognizing increasing and decreasing functions in inequalities?

Tip:

Always pay attention to the base of the exponent. When the base is between 0 and 1, the direction of the inequality changes when you compare the exponents.

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Math Problem Analysis

Mathematical Concepts

Exponential Inequalities
Exponents
Logarithms

Formulas

a^x > a^y implies x > y when a > 1
a^x < a^y implies x < y when 0 < a < 1
Fractional powers and base comparisons

Theorems

Properties of Exponents
Comparing Exponents in Inequalities
Base Conversion Theorem

Suitable Grade Level

Grades 10-12