Math Problem Statement

Two rectangles are shown below. Rectangle P has a perimeter of 20 inches. Rectangle Q has a perimeter of 30 inches. Rectangle P has sides h and j + 4, and Rectangle Q has sides 3h and j + 1. What are the values of j and h?

Solution

We are given two rectangles, P and Q, with the following information:

  • Rectangle P has a perimeter of 20 inches.

    • One side is hh, and the other is j+4j + 4.
  • Rectangle Q has a perimeter of 30 inches.

    • One side is 3h3h, and the other is j+1j + 1.

Perimeter Formulas:

The perimeter PP of a rectangle is given by: P=2×(length+width)P = 2 \times (\text{length} + \text{width})

Setting up the equations:

  1. Rectangle P's Perimeter: 20=2×(h+(j+4))20 = 2 \times (h + (j + 4)) Simplifying: 20=2×(h+j+4)20=2h+2j+812=2h+2j6=h+j20 = 2 \times (h + j + 4) \quad \Rightarrow \quad 20 = 2h + 2j + 8 \quad \Rightarrow \quad 12 = 2h + 2j \quad \Rightarrow \quad 6 = h + j This gives us the first equation: h+j=6(Equation 1)h + j = 6 \quad \text{(Equation 1)}

  2. Rectangle Q's Perimeter: 30=2×(3h+(j+1))30 = 2 \times (3h + (j + 1)) Simplifying: 30=2×(3h+j+1)30=6h+2j+228=6h+2j30 = 2 \times (3h + j + 1) \quad \Rightarrow \quad 30 = 6h + 2j + 2 \quad \Rightarrow \quad 28 = 6h + 2j This gives us the second equation: 6h+2j=28(Equation 2)6h + 2j = 28 \quad \text{(Equation 2)}

Solving the system of equations:

We now have the system of two equations:

  1. h+j=6h + j = 6
  2. 6h+2j=286h + 2j = 28

From Equation 1, solve for jj: j=6hj = 6 - h

Substitute this into Equation 2: 6h+2(6h)=286h+122h=284h+12=284h=16h=46h + 2(6 - h) = 28 \quad \Rightarrow \quad 6h + 12 - 2h = 28 \quad \Rightarrow \quad 4h + 12 = 28 \quad \Rightarrow \quad 4h = 16 \quad \Rightarrow \quad h = 4

Now substitute h=4h = 4 back into Equation 1: 4+j=6j=24 + j = 6 \quad \Rightarrow \quad j = 2

Final Answer:

The values of jj and hh are: j=2,h=4j = 2, \quad h = 4

Would you like further details or have any questions?

Here are 5 follow-up questions for deeper understanding:

  1. How would the solution change if the perimeter of rectangle P was different?
  2. What if rectangle Q had sides proportional to a different constant than 3h3h?
  3. Can you solve for the area of each rectangle using the values of jj and hh?
  4. What other shapes besides rectangles have similar perimeter formulas?
  5. How would you solve for perimeter if one of the dimensions was a variable expression?

Tip: When solving for variables in two equations, always simplify and substitute systematically to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Linear Equations
Perimeter

Formulas

Perimeter of a rectangle: P = 2 * (length + width)

Theorems

System of Equations

Suitable Grade Level

Grades 6-8