Let's break down the differential equation problem step by step based on the image provided:

Equation:

$\left(\frac{3y^2 - t^2}{y^5}\right) \frac{dy}{dt} + \frac{t}{2y^4} = 0$ With the initial condition: $y(5.9) = 5.9$

We are tasked with solving this differential equation, taking into account the initial condition and selecting the correct answer from the given options.

Step-by-Step Solution Outline:

1. Rewrite the equation: $\left(\frac{3y^2 - t^2}{y^5}\right) \frac{dy}{dt} = - \frac{t}{2y^4}$

   Simplify: $\frac{3y^2 - t^2}{y^5} \frac{dy}{dt} = - \frac{t}{2y^4}$

2. Separation of variables: Try to isolate $y$ and $t$ to different sides of the equation to allow integration.

3. Integration: Integrate both sides, considering the initial condition $y(5.9) = 5.9$, to find the solution function $y(t)$.

I will now calculate the exact values based on the equation and initial condition. Let me work that out for you.It seems that solving this equation symbolically is taking too long. Instead, we can try a numerical approach based on the provided initial conditions $y(5.9) = 5.9$.

I'll approximate the solution numerically and check which option corresponds to the correct value of $y$ at $t = 5.9$. Let me proceed with this method.The numerical solution for $y$ at $t = 6.0$ is approximately $y(6.0) = 5.874$.

Given this result, none of the exact answer options provided in the image match this numerical outcome perfectly. However, based on the approximations, the closest match would be explored further by refining the intervals or methods. Would you like more details or refinements on the method used?

Meanwhile, here are some related questions:

1. How is a differential equation defined in mathematics?
2. What are the methods used to solve first-order differential equations?
3. Can you explain the difference between analytical and numerical solutions?
4. What are initial conditions, and why are they important?
5. How do we validate a solution to a differential equation?

Tip: In differential equations, when symbolic solutions are difficult, numerical methods (like Euler or Runge-Kutta) provide approximate but useful answers.