Math Problem Statement

Solve x^2+y =dy/dx , y(0)=1 ,h=0.01,0.05,x(0)=0, using eulars method

Solution

To solve the first-order differential equation dydx=x2+y\frac{dy}{dx} = x^2 + y using Euler's method with initial conditions y(0)=1y(0) = 1, step sizes h=0.01h = 0.01 and h=0.05h = 0.05, and x(0)=0x(0) = 0, we proceed as follows:

Problem Setup:

The differential equation is:

dydx=x2+y\frac{dy}{dx} = x^2 + y

With the initial condition y(0)=1y(0) = 1, we need to apply Euler's method for two different step sizes h=0.01h = 0.01 and h=0.05h = 0.05.

Euler's Method:

Euler's method is a numerical technique for solving differential equations. Given the differential equation dydx=f(x,y)\frac{dy}{dx} = f(x, y) and initial values x0x_0 and y0y_0, the formula for the next point is:

yn+1=yn+hf(xn,yn)y_{n+1} = y_n + h \cdot f(x_n, y_n) xn+1=xn+hx_{n+1} = x_n + h

Where f(xn,yn)=xn2+ynf(x_n, y_n) = x_n^2 + y_n.

Step-by-Step Approach:

  1. Start at x=0x = 0 with y(0)=1y(0) = 1.
  2. Apply the Euler's formula to compute the next values of yy and xx for each step.

Now, I will compute the values for each step size. Let's begin with h=0.01h = 0.01 and h=0.05h = 0.05. I'll calculate the values numerically for the first few steps.

For h=0.01h = 0.01:

  1. At x0=0x_0 = 0, y0=1y_0 = 1: y1=1+0.01(02+1)=1.01y_1 = 1 + 0.01 \cdot (0^2 + 1) = 1.01 x1=0+0.01=0.01x_1 = 0 + 0.01 = 0.01
  2. At x1=0.01x_1 = 0.01, y1=1.01y_1 = 1.01: y2=1.01+0.01(0.012+1.01)=1.01+0.01(0.0001+1.01)=1.010+0.0101=1.0201y_2 = 1.01 + 0.01 \cdot (0.01^2 + 1.01) = 1.01 + 0.01 \cdot (0.0001 + 1.01) = 1.010 + 0.0101 = 1.0201 x2=0.01+0.01=0.02x_2 = 0.01 + 0.01 = 0.02

For h=0.05h = 0.05:

  1. At x0=0x_0 = 0, y0=1y_0 = 1: y1=1+0.05(02+1)=1.05y_1 = 1 + 0.05 \cdot (0^2 + 1) = 1.05 x1=0+0.05=0.05x_1 = 0 + 0.05 = 0.05
  2. At x1=0.05x_1 = 0.05, y1=1.05y_1 = 1.05: y2=1.05+0.05(0.052+1.05)=1.05+0.05(0.0025+1.05)=1.05+0.051.0525=1.05+0.052625=1.102625y_2 = 1.05 + 0.05 \cdot (0.05^2 + 1.05) = 1.05 + 0.05 \cdot (0.0025 + 1.05) = 1.05 + 0.05 \cdot 1.0525 = 1.05 + 0.052625 = 1.102625 x2=0.05+0.05=0.10x_2 = 0.05 + 0.05 = 0.10

I can continue calculating more steps or generate tables for these computations. Would you like to see a complete table for both step sizes h=0.01h = 0.01 and h=0.05h = 0.05 up to a specific value of xx? Or would you like further details on any part?

Follow-Up Questions:

  1. Would you like to see the results for a larger interval of xx?
  2. Should we use a different numerical method like Runge-Kutta for comparison?
  3. Do you need help visualizing these results on a graph?
  4. Should we investigate the effect of using smaller or larger step sizes?
  5. Would you like an explanation of how Euler’s method accuracy is affected by hh?

Tip: Euler's method is easy to implement but can be inaccurate for stiff equations or when larger step sizes are used. Smaller step sizes yield more accurate results.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Numerical Methods
Euler's Method

Formulas

Euler's method: y_(n+1) = y_n + h * f(x_n, y_n)
Differential equation: dy/dx = x^2 + y

Theorems

Euler's Method for solving first-order ODEs

Suitable Grade Level

Undergraduate Level (Math/Engineering students)