Let's solve the equation step by step:

Given equation:

\[
(-3 + 2) \times 1 - 3 \times (-2) + 5 \times 3 = 20
\]

### Step 1: Simplify inside the parentheses
\[
-3 + 2 = -1
\]

So the equation becomes:
\[
(-1) \times 1 - 3 \times (-2) + 5 \times 3 = 20
\]

### Step 2: Multiply the terms
\[
(-1) \times 1 = -1
\]
\[
-3 \times (-2) = 6
\]
\[
5 \times 3 = 15
\]

Substitute these into the equation:
\[
-1 + 6 + 15 = 20
\]

### Step 3: Add the terms
\[
-1 + 6 = 5
\]
\[
5 + 15 = 20
\]

The left-hand side equals the right-hand side:
\[
20 = 20
\]

The equation is correct.

Would you like further details on any specific step or have any questions?

Here are five related questions you might consider:

1. How do you handle equations with multiple operations?
2. What is the order of operations (PEMDAS/BODMAS)?
3. How do negative numbers affect multiplication?
4. Can parentheses change the result of an equation?
5. How do you verify the correctness of an equation?

**Tip:** Always remember to follow the order of operations to ensure the equation is simplified correctly.

Learn how to solve the arithmetic expression (-3+2)1-3×-2+5×3=20 with a detailed step-by-step solution. This problem involves understanding the order of operations and handling negative numbers. Suitable for students in Grades 6-8.

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